友友们,有没有一种方法,我想让最后一行的加号和倒数第二行的等号对齐,不要那种前三个等号对齐那种
begin{equation}label{h5}
\left\{
\begin{aligned}
&\dot{X}(t)=AX(t)+Bw(0,t), &&t\in(0,T),\\
&w_t(x,t)-w_{xx}(x,t)=0, &&x\in[0,D],t\in(0,T),\\
&w(0,t)=\gamma(D)X(t)\\
&\displaystyle{
+\int_{0}^{D}\left(\int_{0}^{D-y}\gamma(\sigma)d\sigma\right) Bu(y,t)dy},&& t\in(0,T),
\end{aligned}
\right.
end{equation}
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{cases}
\dot{X}(t)=\operatorname{AX}(t)+\operatorname{Bw}(0,t), & t\in(0,T), \\
w_t(x,t)-w_{xx}(x,t)=0, & x\in[0,D],t\in(0,T), \\
\begin{aligned}
w(0,t)={} & \gamma(D)\operatorname{X}(t) \\
& +\int_{0}^{D}\Bigl(\int_{0}^{D-y}\gamma(\sigma)d\sigma\Bigr) \operatorname{Bu}(y,t)\,\mathrm{d}y, \\
\end{aligned}
& t\in(0,T), \\
\end{cases}
\end{equation}
\end{document}
一个简单粗暴的方法,但自由度比较高:
\begin{equation}
\left\{
\begin{aligned}
&\dot{X}(t)=AX(t)+Bw(0,t), &&t\in(0,T),\\
&w_t(x,t)-w_{xx}(x,t)=0, &&x\in[0,D],t\in(0,T),\\
&w(0,t)=\gamma(D)X(t)\\
&\hspace*{3.1em} \displaystyle{
+\int_{0}^{D}\left(\int_{0}^{D-y}\gamma(\sigma)d\sigma\right) Bu(y,t)dy},&& t\in(0,T),
\end{aligned}
\right.
\end{equation}
应该有特定的环境支持,一时想不起来了。