这个问题本质上和 matrix 没有丝毫关系
\documentclass{article}
\usepackage{tikz, bm, lipsum}
\usetikzlibrary{scopes}
\begin{document}
\lipsum[1][1-4]
\begin{center}
\begin{tikzpicture}
\node[font=\large] {$\bm{R_0} = $};
\draw[thick] (1.2,2)--(1,2)--(1,-2)--(1.2,-2);
{[]
\draw (2,0.9)--(2,-1.8) (2.5,0.9)--(2.5,-1.8) (3,0.9)--(3,-1.8);
\node[font=\scriptsize] at (2.5,1.15){$K$};
\node[font=\large] at (3.15,-2.15){\bm{$S$}}; }
{[shift={(4.7,0.2)}]
\node[draw,minimum size=1.7cm,label={[above=0.5,font=\scriptsize]$K$},
label={[right=1.35cm,below=1.25cm,font=\scriptsize]$K$}] (m) {};
\node[font=\large] at(0.3,-2.4) {$E(\bm{aa}^H)$};
}
{[shift={(7,0.2)}]
\draw (0,0)--(2.8,0) (0,0.62)--(2.8,0.62) (0,-0.62)--(2.8,-0.62);
\node[font=\scriptsize] at(1.35,1.3){$M$};
\node[font=\scriptsize] at(3.3,0.1){$K$};
\node[font=\large] at(1.7,-2.4) {$\bm{S}^H$};
}
\draw[thick] (10.9,2)--(11.1,2)--(11.1,-2)--(10.9,-2);
\node[font=\large,align=center] at(6,-3.1) {\scalebox{0.9}[1.5]{$\uparrow$} \\[1ex] non-singular};
\end{tikzpicture}
\end{center}
\lipsum[1][1-4]
\end{document}












问 绘制如下形式的「抽象」矩阵的最佳实践?