如图,请问各位大佬,我该如何得到这个质数求和公式呀?
我目前得到的结果如下:
这个求和号后边的撇位置不太对,该如何解决呀?
...
\usepackage{physics2}
...
\begin{align}
\ket[big] {\psi_{n\kk}^{(1)}} = \sum_{n'\kk'}{}^{\prime}\ket[big] {\psi_{n'\kk'}^{(0)} } \frac{ \braket[3,big] {\psi_{n'\kk'}^{(0)}} {\hat{V}} {\psi_{n\kk}^{(0)}} }{ \varepsilon_{n\kk}^{(0)} - \varepsilon_{n'\kk'}^{(0)} }
\end{align}
$$
\left|\psi_{n \mathbf{k}}^{(1)}\right\rangle=\boxed{\sum_{n^{\prime} \mathbf{k}^{\prime}}} ^\prime \left|\psi_{n^{\prime} \mathbf{k}^{\prime}}^{(0)}\right\rangle \frac{\left\langle\psi_{n^{\prime} \mathbf{k}^{\prime}}^{(0)}|\hat{V}| \psi_{n \mathbf{k}}^{(0)}\right\rangle}{\varepsilon_{n \mathbf{k}}^{(0)}-\varepsilon_{n^{\prime} \mathbf{k}^{\prime}}^{(0)}} .
$$