10 请问 Tikz 如何画出矢量和三个坐标轴的夹角？

谢谢！我想要的是表示出三个夹角，如果用 3dplot 画出的角是平面的，很难看。我通过笨方法实现了。

完美实现了。但是代码不够好看。

代码如下：

begin{tikzpicture}[>=latex,scale=0.7,line width=0.6pt]

coordinate (o) at (0,0);
coordinate (x) at (220:3);
coordinate (y) at (0:6);
coordinate (z) at (90:6);
coordinate (a) at (50:5);

draw [->] (o) node [below]{$O$} --(x) node [below]{$x$};
draw [->] (o)--(y) node [below]{$y$};
draw [->] (o)--(z) node [right]{$z$};
draw [->,hmain] (o)--(a) node [right]{$\vec{A}$};

draw [->,hmain] ($(o)!0.25!(a)$) to [bend right] node[above left]{$\alpha$}($(o)!.3!(x)$);
draw [->,hmain] ($(o)!0.25!(a)$) to [bend left] node[right]{$\beta$}($(o)!.2!(y)$);
draw [->,hmain] ($(o)!0.25!(a)$) to [bend right] node[above]{$\gamma$}($(o)!.2!(z)$);

draw[densely dotted] (a)--(0:3.2);
draw[densely dotted] (a)--(90:5) coordinate (az);
draw[densely dotted] (a)--(340:3.4);
draw[densely dotted] (o)--(340:3.4);
draw[densely dotted] (0:4.4) coordinate (ay) --(340:3.4);
draw[densely dotted] (220:1.8) coordinate (ax)--(340:3.4);

draw [->,hred] (o)--(ax) node [above left]{$\vec{A}_x$};
draw [->,hred] (o)--(ay) node [above]{$\vec{A}_y$};
draw [->,hred] (o)--(az) node [left]{$\vec{A}_z$};

end{tikzpicture}