请问这种表格带颜色，且色条长度反映了表格数据长度，这类表格该如何绘制

3 个回答

shadow 2025-08-28

这个人懒得不得了，竟然啥也没写

用 tikz 的 matrix 实现。思路是先画顶部两行表格，再画左边绿色区域的表格，最后画中间的带彩色数据条的表格，中间表格分块画，每一块都是一个 matrix. 中间表格先输入内容，然后用 foreach 加 fill 填充彩色数据条，最后给表格整体用绿色背景，然后在中间区域覆盖白色背景。中间表格我做了一部分，剩余内容和前两行的同理，有兴趣可以自己补充。

\documentclass[border=1cm,tikz]{standalone}
\usepackage{xcolor}
\usetikzlibrary{scopes,matrix,calc,backgrounds,fit}

\definecolor{blue1}{RGB}{51,204,255}
\definecolor{blue2}{RGB}{51,153,255}

\begin{document}
\begin{tikzpicture}[thick]

  % 顶部表格
  {[thick]
    \matrix(m)[matrix of nodes,nodes={minimum width=5.4cm, minimum height=0.7cm}, ]{
      \hskip-1.4cm Parameter & Ep1 $(b_p=0.04)$ & Ep2 $(b_p=0.02)$ & Ep3 $(b_p=0.01)$\\
      \hskip-1.4cm Strategy & S1 \hskip3.6em S2 \hskip3.6em S3 &  S1 \hskip3.6em S2 \hskip3.6em S3 &  S1 \hskip3.6em S2 \hskip3.6em S3\\
    };

    \draw(m-1-4.south east)--++(-23.2,0);
    \draw[line width=1.3pt](m-2-4.south east)--++(-23.2,0);
    \draw[line width=1pt,double](m-1-4.north east)--++(-23.2,0);
    \draw(m-1-1.north east)--(m-2-1.south east)--++(0,-13.6) (m-1-2.north east)--(m-2-2.south east)--++(0,-13.6) (m-1-3.north east)--(m-2-3.south east)--++(0,-13.6);
  }

  % 左边表格
  {[shift={(-8.2,-7.4)}]
    \matrix(n) [matrix of nodes,nodes={text width=2.5cm,text height=0.5cm,execute at begin node={\setlength{\baselineskip}{4ex}}, anchor=center, },align=center] {
      {Efficiency \\ change [pu]}  & {Avg-HPP 1\\Min-HPP 1\\Avg-Hpp 2\\Min-HPP 2} \\
      {GV movement\\ {[/]}}  & {Distance\\Amount} \\
      {RB movement\\ {[pu]}}  & {Dist.-HPP 1\\Dist.-HPP 2\\Amount-HPP 1\\Amount-HPP 2} \\
      {Frequency \\ quanlity [pu]}  & {HPP 1\\HPP 2} \\
      {Mileage\\ {[MW]}}  & {HPP 1\\HPP 2} \\
      Strength [pu] & {HPP 1\\HPP 2} \\
      Mileage [pu] & {HPP 1\\HPP 2} \\
      Contributiuon [pu] & {HPP 1\\HPP 2} \\
    };

    \draw[line width=1pt,double](n-8-1.south west) ++(0,-2mm)--++(21.775,0) (n-8-1.south west) ++(0,-2mm)--++(-1.5,0);
    \draw[line width=1.3pt] (n-8-1.south west) ++(0,-2mm)--(n-1-1.north west)--++(0,0.5);
    \draw(n-2-1.north west)++(0,-2mm)--++(21.775,0) (n-2-1.south west)++(0,-1mm)--++(21.775,0)
    (n-5-1.north west)++(0,-2mm)--++(21.775,0) (n-6-1.north west)++(0,1mm)--++(21.775,0) (n-6-1.north west)++(0,1mm)--++(-1.5,0);
    \draw[line width=1.3pt](n-4-1.north west)++(0,-2mm)--++(21.775,0) (n-4-1.north west)++(0,-2mm)--++(-1.5,0);

    \node[rotate=90]at ($(n-2-1.west)+(-8mm,-1.5mm)$){\large Burden};
    \node[rotate=90,align=center,font=\large]at ($(n-4-1.west)+(-8mm,-9mm)$){Regulation\\performance};
    \node[rotate=90]at ($(n-7-1.west)+(-8mm,-1.5mm)$){\large Payment};
  }

  % 中间第一行表格
  {[shift={(m-2-2.south)}, yshift=-1.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      -0.079\% & -0.097\% & -0.144\%\\
      -0.268\% & -0.297\% & -0.304\%\\
      -0.030\% & -0.061\% & -0.196\%\\
      -0.435\% & -0.472\% & -0.638\%\\
    };
    \foreach \x/\y in{%
      1-1/0.079, 1-2/0.087, 1-3/0.12,
      2-1/0.19, 2-2/0.19, 2-3/0.21,
      3-1/0.030, 3-2/0.041, 3-3/0.13,
      4-1/0.28, 4-2/0.3, 4-3/0.35
    }
    {\fill[red, opacity=0.55](p1-\x.north east) rectangle ++ (-\y,-0.5);
    }
  }

  {[shift={(m-2-3.south)}, yshift=-1.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      -0.217\% & -0.249\% & -0.535\%\\
      -0.493\% & -0.535\% & -0.729\%\\
      -0.125\% & -0.153\% & -0.743\%\\
      -0.627\% & -0.653\% & -1.369\%\\
    };
    \foreach \x/\y in{%
      1-1/0.199, 1-2/0.207, 1-3/0.37,
      2-1/0.35, 2-2/0.35, 2-3/0.43,
      3-1/0.070, 3-2/0.071, 3-3/0.44,
      4-1/0.38, 4-2/0.4, 4-3/0.75
    }
    {\fill[red, opacity=0.55](p1-\x.north east) rectangle ++ (-\y,-0.5);
    }
  }

  {[shift={(m-2-4.south)}, yshift=-1.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      -0.0726\% & -0.771\% & -1.941\%\\
      -1.034 \% & -1.069\% & -2.232\%\\
      -0.528\% & -0.555\% & -2.505\%\\
      -1.276\% & -1.300\% & -3.182\%\\
    };
    \foreach \x/\y in{%
      1-1/0.4, 1-2/0.42, 1-3/1.1,
      2-1/0.6, 2-2/0.6, 2-3/1.3,
      3-1/0.32, 3-2/0.35, 3-3/1.42,
      4-1/0.68, 4-2/0.7, 4-3/1.65
    }
    {\fill[red, opacity=0.55](p1-\x.north east) rectangle ++ (-\y,-0.5);
    }
  }

  % 中间第二行表格
  {[shift={(m-2-2.south)}, yshift=-3.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      7.610 & 7.610 & 7.610\\
      2066 & 2066 & 2066\\
    };
    \foreach \x/\y in{%
      1-1/0.4, 1-2/0.4, 1-3/0.4
    }
    {\fill[blue1,opacity=0.4](p1-\x.north west)++(0.04,0.05) rectangle ++ (\y,-0.6);}
    \foreach \x/\y in{%
      2-1/1.3, 2-2/1.3, 2-3/1.3
    }
    {\fill[blue!80!green, opacity=0.4](p1-\x.north west)++(0.01,-0.05) rectangle ++ (\y,-0.5);}

  }

  {[shift={(m-2-3.south)}, yshift=-3.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      15.634 & 15.634 & 15.634\\
      2343 & 2343 & 2343\\
    };
    \foreach \x/\y in{%
      1-1/0.7, 1-2/0.7, 1-3/0.7
    }
    {\fill[blue1,opacity=0.4](p1-\x.north west)++(0.04,0.05) rectangle ++ (\y,-0.6);}
    \foreach \x/\y in{%
      2-1/1.5, 2-2/1.5, 2-3/1.5
    }
    {\fill[blue!80!green, opacity=0.4](p1-\x.north west)++(0.01,-0.05) rectangle ++ (\y,-0.5);}

  }

  {[shift={(m-2-4.south)}, yshift=-3.35cm]
    \matrix(p1)[matrix of nodes, nodes={minimum width=1.8cm, minimum height=0.6cm,}, column sep=0.cm]{
      31.829 & 31.829 & 31.829\\
      2676 & 2676 & 2676\\
    };
    \foreach \x/\y in{%
      1-1/1.6, 1-2/1.6, 1-3/1.6
    }
    {\fill[blue1,opacity=0.4](p1-\x.north west)++(0.04,0.05) rectangle ++ (\y,-0.6);}
    \foreach \x/\y in{%
      2-1/1.75, 2-2/1.75, 2-3/1.75
    }
    {\fill[blue!80!green, opacity=0.4](p1-\x.north west)++(0.01,-0.05) rectangle ++ (\y,-0.5);}

  }

  % 背景
  {[on background layer]
    \fill[green!40,opacity=0.3](current bounding box.south east)++(0.2,-0.2) rectangle +(-23.8,15.6);
    \fill[white](current bounding box.south east)++(-0.3,0.25) rectangle +(-16.2,13.6);
  }
\end{tikzpicture}
\end{document}

以上过程是平凡但较繁琐的。

latex小白 2025-08-28

这家伙很懒，什么也没写！

嗯嗯谢谢大神

shadow 2025-08-28

这个人懒得不得了，竟然啥也没写

@u156710 说难也不难，可以分步绘制，先画表格，每个区块可以看作一个 node，然后填内容，数据条可以目测，如果不要求太精确是可以行得通的。有空我会试试完成一部分。

Sagittarius Rover 2025-08-28

这家伙很懒，什么也没写！

@u26254 感觉这样的话可拓展性会相对比较差...

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远方不远 2025-08-28

Hello, LuaLaTeX！

请不要把LaTeX当成万能的工具！

Sagittarius Rover 2025-08-28

这家伙很懒，什么也没写！

或者绘制思路也行，谢谢谢谢谢谢谢谢

我的建议是看一下tabularray(v2025A)的5.5节和5.10节的内容

使用functional库按行计算最大值，同时计算当前格与行内最大值的占比
使用tikz库实现对相应比例长度的格子绘制

不过具体实现有可能会遇到一些障碍...

@u156710 BTW，请补充同一行内：

所有数均为正数
所有数均为负数
有正数也有负数

的时候，如何确定每个单元格内「数据条」的长度，如何确定填充是从左往右还是从右往左？最好补充三个例子来说明这一种预期的填充方式。

一些相关的信息：这一功能在excel里与「数据条」类似

latex小白 2025-08-28

这家伙很懒，什么也没写！

谢谢大神！太强了

Sagittarius Rover 2025-08-28

这家伙很懒，什么也没写！

@u156710 搓出来再说吧...

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Sagittarius Rover 2025-08-28

这家伙很懒，什么也没写！

Thanks to Jasper Habicht!

最初的尝试 version1

一个可能的答案如下：

\documentclass{article}
\usepackage{libertinus-otf}
\usepackage[landscape]{geometry}
\usepackage{tabularray}
\UseTblrLibrary{functional, tikz}
\IgnoreSpacesOn
\tlNew \gTikzPathsTlpositive
\tlNew \gTikzPathsTlnegative
\clistNew \lCurrentRowDataClist
\prgNewFunction \RowMax {m} {%
    \prgReturn {\fpEval {max(#1)}}
}
\prgNewFunction \RowMin {m} {%
    \prgReturn {\fpEval {min(#1)}}
}
\prgNewFunction \DrawDataBar { m m } {%
    \tlClear \gTikzPathsTl%
    \intStepOneInline {#1} {\arabic{rowcount}} {%
        \clistSet \lCurrentRowDataClist {}
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \clistPutRight \lCurrentRowDataClist {\cellGetText {##1} {####1} }
        }
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \fpSet \lTmpaFp {\RowMax{\expValue \lCurrentRowDataClist}}
            \fpSet \lTmpbFp {\RowMin{\expValue \lCurrentRowDataClist}}
            \fpSet \lTmpcFp {\cellGetText {##1} {####1} }
            \fpSet \lTmpiFp {%
                \fpMathDiv {\fpUse \lTmpcFp} {\fpUse \lTmpaFp}
            }%
            \fpSet \lTmpjFp {%
                \fpMathDiv {\fpUse \lTmpcFp} {\fpUse \lTmpbFp}
            }%
            \fpCompareTF {\lTmpaFp} > {\cZeroFp}{
                \tlPutRight \gTikzPathsTlpositive {%
                    \evalWhole {%
                        ([shift={(.5pt,.5pt)}]##1-####1.south~west) rectangle 
                        ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpiFp}!(##1-####1.north~east)$)
                    }%
                }%
            }{%
                \tlPutRight \gTikzPathsTlnegative {%
                    \evalWhole {%
                        ([shift={(-.5pt,-.5pt)}]##1-####1.north~east) rectangle 
                        ([shift={(.5pt,.5pt)}]$(##1-####1.south~east)!{\fpUse \lTmpjFp}!(##1-####1.south~west)$)
                    }%
                }%
            }
        }
    }
}
\IgnoreSpacesOff
\begin{document}

\begin{tblrtikzbelow}
   \fill [violet!80] \gTikzPathsTlpositive;
   \fill [magenta!80] \gTikzPathsTlnegative;
\end{tblrtikzbelow}
\begin{tblr}{
    colspec={*{5}{Q[c,3cm]}},
    hlines, vlines,
    row{1} = {bg=lightgray},
    process=\DrawDataBar{2}{1}
}
    Item1 & Item2 & Item3 & Item4 & Item5 \\
    1 & 2 & 3 & 4 & 5 \\
    6.5 & 5.4 & 4.3 & 3.2 & 2.1 \\
    -1 & -2 & -3 & -4 & -5 \\
    -6.5 & -5.4 & -4.3 & -3.2 & -2.1 \\
    0.5 & 1.5 & 2.5 & 3.5 & 4.5 \\
    -0.5 & -1.5 & -2.5 & -3.5 & -4.5 \\
    -5.5 & -6.5 & -7.5 & -8.5 & -9.5 \\
    -3.1 & -2.1 & -1.1 & -0.1 & -1.1 \\
    1 & 4 & 2 & 8 & 5 \\
    5.5 & 6.5 & 7.5 & 8.5 & 9.5 \\
\end{tblr}

\end{document}

由于我没想好关于「同一行内既有正数也有负数」应该如何绘制，因此\fpCompareTF的判断应该也有一定的修改空间...目前只支持全正/全负的同一行数字，且个人认为用户接口并不太友好...

Edit: 直接增加功能version2

增加了对于行内数字有正有负形式的支持：

\documentclass{article}
\usepackage{libertinus-otf}
\usepackage[landscape]{geometry}
\usepackage{tabularray}
\UseTblrLibrary{functional, tikz}
\IgnoreSpacesOn
\tlNew \gTikzPathsTlpositive
\tlNew \gTikzPathsTlnegative
\tlNew \gTikzPathsTlcrosspositive
\tlNew \gTikzPathsTlcrossnegative

\clistNew \lCurrentRowDataClist
\prgNewFunction \RowMax {m} {%
    \prgReturn {\fpEval {max(#1)}}
}
\prgNewFunction \RowMin {m} {%
    \prgReturn {\fpEval {min(#1)}}
}
\prgNewFunction \DrawDataBar { m m } {%
    \tlClear \gTikzPathsTl%
    \intStepOneInline {#1} {\arabic{rowcount}} {%
        \clistSet \lCurrentRowDataClist {}
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \clistPutRight \lCurrentRowDataClist {\cellGetText {##1} {####1} }
        }
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \fpSet \lTmpaFp {\RowMax{\expValue \lCurrentRowDataClist}}
            \fpSet \lTmpbFp {\RowMin{\expValue \lCurrentRowDataClist}}
            \fpSet \lTmpcFp {\cellGetText {##1} {####1} }
            \fpSet \lTmpiFp {%
                \fpMathDiv {\fpUse \lTmpcFp} {\fpUse \lTmpaFp}
            }%
            \fpSet \lTmpjFp {%
                \fpMathDiv {\fpUse \lTmpcFp} {\fpUse \lTmpbFp}
            }%
            \fpSet \lTmpkFp {%
                \fpEval {( 0 - \fpUse \lTmpbFp) / (\fpUse \lTmpaFp - \fpUse \lTmpbFp)}
            }%
            \fpSet \lTmppFp {%
                \fpEval {(\fpUse \lTmpcFp - \fpUse \lTmpbFp) / (\fpUse \lTmpaFp - \fpUse \lTmpbFp)}
            }%
            \fpCompareTF {\lTmpaFp} > {\cZeroFp}{
                \fpCompareTF {\lTmpbFp} > {\cZeroFp}{%
                    % case1: max>0 min>0
                    \tlPutRight \gTikzPathsTlpositive {%
                        \evalWhole {%
                            ([shift={(.5pt,.5pt)}]##1-####1.south~west) rectangle 
                            ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpiFp}!(##1-####1.north~east)$)
                        }%
                    }%
                }{
                    % case2: max>0 min<0
                    \fpCompareTF {\lTmpcFp} < {\cZeroFp}{%
                    % 如果当前值比0小，则从「\lTmppFp到\lTmpkFp」
                        \tlPutRight \gTikzPathsTlcrossnegative {%
                            \evalWhole {%
                                ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmppFp}!(##1-####1.south~east)$) 
                                rectangle 
                                ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpkFp}!(##1-####1.north~east)$)
                            }
                        }
                    }{%% 如果当前值比0大，则从「\lTmpkFp到\lTmppFp」
                        \tlPutRight \gTikzPathsTlcrosspositive {%
                        \evalWhole {%
                                ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmpkFp}!(##1-####1.south~east)$) 
                                rectangle 
                                ([shift={(-.5pt,.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmppFp}!(##1-####1.north~east)$)
                            }
                        }
                    }
                }
            }{%
                % case3: max<0 min<0
                \tlPutRight \gTikzPathsTlnegative {%
                    \evalWhole {%
                        ([shift={(-.5pt,-.5pt)}]##1-####1.north~east) rectangle 
                        ([shift={(.5pt,.5pt)}]$(##1-####1.south~east)!{\fpUse \lTmpjFp}!(##1-####1.south~west)$)
                    }%
                }%
            }
        }
    }
}
\IgnoreSpacesOff
\begin{document}

\begin{tblrtikzbelow}
   \fill [violet!80] \gTikzPathsTlpositive;
   \fill [magenta!80] \gTikzPathsTlnegative;
   \fill [green!80] \gTikzPathsTlcrosspositive;
   \fill [cyan!80] \gTikzPathsTlcrossnegative;
\end{tblrtikzbelow}
\begin{tblr}{
    colspec={*{5}{Q[c,3cm]}},
    hlines, vlines,
    row{1} = {bg=lightgray},
    process=\DrawDataBar{2}{1}
}
    Item1 & Item2 & Item3 & Item4 & Item5 \\
    0.5 & 1.5 & 2.5 & 3.5 & 4.5 \\
    -1 & -2 & -3 & -4 & -5 \\
    -6.5 & -5.4 & -4.3 & -3.2 & -2.1 \\
    6.5 & -5.4 & 4.3 & -3.2 & 2.1 \\
    -0.5 & -1.5 & -2.5 & -3.5 & -4.5 \\
    -5.5 & -6.5 & -7.5 & -8.5 & -9.5 \\
    -1 & 2 & -3 & 4 & -5 \\
    -3.1 & -2.1 & -1.1 & 1 & -1.1 \\
    1 & 4 & 2 & 8 & 5 \\
    5.5 & 6.5 & 7.5 & 8.5 & 9.5 \\
\end{tblr}

\end{document}

嗯...但他目前也有缺点，似乎暂时缺少对填充的数字为「0」时的支持，同时个人觉得条件判断的逻辑写复杂了，代码仍然有很大的改进空间...

Re-Edit:version3

完善了条件逻辑...但好像也并不完善，优化了坐标点位的命名，补充对「0」这一边界点的支持：

\documentclass{article}
\usepackage{libertinus-otf}
\usepackage[landscape]{geometry}
\usepackage{tabularray}
\UseTblrLibrary{functional, tikz}
\IgnoreSpacesOn
\tlNew \gTikzPathsTlpositive
\tlNew \gTikzPathsTlnegative
\tlNew \gTikzPathsTlcrosspositive
\tlNew \gTikzPathsTlcrossnegative

\clistNew \lCurrentRowDataClist
\prgNewFunction \RowMax {m} {%
    \prgReturn {\fpEval {max(#1)}}
}
\prgNewFunction \RowMin {m} {%
    \prgReturn {\fpEval {min(#1)}}
}
\prgNewFunction \DrawDataBar { m m } {%
    \tlClear \gTikzPathsTl%
    \intStepOneInline {#1} {\arabic{rowcount}} {%
        \clistSet \lCurrentRowDataClist {}
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \clistPutRight \lCurrentRowDataClist {\cellGetText {##1} {####1} }
        }
        \fpSet \lTmpmaxFp {\RowMax{\expValue \lCurrentRowDataClist}}
        \fpSet \lTmpminFp {\RowMin{\expValue \lCurrentRowDataClist}}
        \intStepOneInline {#2} {\arabic{colcount}} {%
            \fpSet \lTmpnowFp {\cellGetText {##1} {####1} }
            % cond1: min>0
            \fpCompareT {\lTmpminFp} > {\cZeroFp} {
                \fpSet \lTmpstartFp { \cZeroFp}
                \fpSet \lTmpendFp { \fpEval {( \lTmpnowFp - \cZeroFp  ) / ( \lTmpmaxFp - \cZeroFp ) }}
                \tlPutRight \gTikzPathsTlpositive {%
                    \evalWhole {%
                        ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmpstartFp}!(##1-####1.south~east)$) 
                        rectangle 
                        ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpendFp}!(##1-####1.north~east)$)
                    }
                }
            }
            % cond2: max<0
            \fpCompareT {\lTmpmaxFp} < {\cZeroFp} {
                % \fpSet \lTmpstartFp {\fpEval {( \cZeroFp - \lTmpnowFp ) / ( \cZeroFp - \lTmpminFp ) }}% 好像有点不对称...
                \fpSet \lTmpstartFp {\fpEval {\cOneFp - ( \lTmpnowFp - \cZeroFp ) / ( \lTmpminFp - \cZeroFp ) }}
                \fpSet \lTmpendFp {\cOneFp}
                \tlPutRight \gTikzPathsTlnegative {%
                    \evalWhole {%
                        ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmpstartFp}!(##1-####1.south~east)$) 
                        rectangle 
                        ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpendFp}!(##1-####1.north~east)$)
                    }
                }
            }
            % cond3: min < 0 < max 
            \fpCompareT {\lTmpminFp} < {\cZeroFp} {
                \fpCompareT {\lTmpmaxFp} > {\cZeroFp} {
                    %% cond3进入判断
                    \fpSet \lTmpzeroFp { \fpEval {( \cZeroFp - \lTmpminFp ) / ( \lTmpmaxFp - \lTmpminFp )}}
                    \fpSet \lTmppointFp {
                        \fpEval { ( \lTmpnowFp - \lTmpminFp ) / ( \lTmpmaxFp - \lTmpminFp ) }
                    }
                    \fpCompareTF {\lTmpnowFp} < {\cZeroFp} {
                        % 分类绘制
                            \tlPutRight \gTikzPathsTlcrossnegative {%
                            \evalWhole {%
                                ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmppointFp}!(##1-####1.south~east)$) 
                                rectangle 
                                ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmpzeroFp}!(##1-####1.north~east)$)
                            }
                        }
                    } {
                        \tlPutRight \gTikzPathsTlcrosspositive {%
                            \evalWhole {%
                                ([shift={(.5pt,.5pt)}]$(##1-####1.south~west)!{\fpUse \lTmpzeroFp}!(##1-####1.south~east)$) 
                                rectangle 
                                ([shift={(-.5pt,-.5pt)}]$(##1-####1.north~west)!{\fpUse \lTmppointFp}!(##1-####1.north~east)$)
                            }
                        }
                    }
                }
            }
        }
    }
}
\IgnoreSpacesOff
\begin{document}

\begin{tblrtikzbelow}
   \fill [violet!80] \gTikzPathsTlpositive;
   \fill [magenta!80] \gTikzPathsTlnegative;
   \fill [green!80] \gTikzPathsTlcrosspositive;
   \fill [cyan!80] \gTikzPathsTlcrossnegative;
\end{tblrtikzbelow}
\begin{tblr}{
    colspec={*{5}{Q[c,3cm]}},
    hlines, vlines, %stretch = 0,
    row{1} = {bg=lightgray,font=\bfseries\large},
    process=\DrawDataBar{2}{1}
}
    Item1 & Item2 & Item3 & Item4 & Item5 \\
    0.5 & 1.5 & 2.5 & 3.5 & 4.5 \\
    -1 & -2 & -3 & -4 & -5 \\
    -6.5 & -5.4 & -4.3 & -3.2 & -2.1 \\
    6.5 & -5.4 & 0 & -3.2 & 2.1 \\
    -0.5 & -1.5 & -8.5 & -3.5 & -4.5 \\
    -5.5 & -9.5 & -2.5 & -7.5 & -6.5\\
    -1 & 2 & -3 & 4 & -5 \\
    -3.1 & -2.1 & -1.1 & 1 & -1.1 \\
    1 & 4 & 2 & 8 & 5 \\
    5.5 & 6.5 & 7.5 & 8.5 & 9.5 \\
\end{tblr}

\end{document}

Sagittarius Rover 2025-08-29

这家伙很懒，什么也没写！

忽然发现OP的原图中，作为参考的最大值的是「一个矩形区域」而不只是「行内」的范围，那这样的话要设计优雅的用户接口可能比较困难了...

Sagittarius Rover 2025-09-01

这家伙很懒，什么也没写！

就留给有缘人自己补充修改一个「统计全表占比」的代码版本了，逻辑清晰简单...

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请问这种表格带颜色，且色条长度反映了表格数据长度，这类表格该如何绘制

最初的尝试 version1

Edit: 直接增加功能version2

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请问这种表格带颜色，且色条长度反映了表格数据长度，这类表格该如何绘制

最初的尝试 version1

Edit: 直接增加功能version2

Re-Edit:version3

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