- 计算宽度要用 interrupt 环境，直接在绘图环境里是不行的。
- blur shadow 里创建了新的绘图环境，盲猜是因为这个把原本的 bottom 图层清空了，解决办法同 1，把标题样式放到单独的绘图环境，先让它画完这部分，就不会被后面影响了。
- 分别在 extra unbroken/first/middle/last 里使用 /tcb/interior code 重写 interior，让 first 末尾的颜色等于 middle 开始的颜色，依此类推，但 middle 部分最好不使用渐变，因为 tcb 好像没有直接判断是否是 unbroken 还是 first-middle-last 还是 first-last，需要 hack。
我实现了 1，2。对于 3，middle 不使用渐变的情况下应该不难。
\documentclass[12pt]{ctexbook}
\usepackage{lipsum}
\usepackage[margin=2cm]{geometry}
\RequirePackage{cncolours,newtx}
\RequirePackage{etoolbox} % 判断函数
\RequirePackage{tikz,calc} %%页面样式设计核心包 %提供\pgfonlayer命令
\usetikzlibrary{cd,calc,shadows,shadows.blur,hobby,intersections, decorations.markings, decorations.pathreplacing,spy,arrows,shapes,fadings,trees,mindmap,patterns,shapes.arrows,shapes.symbols,tikzmark,shapes.geometric,graphs, quotes, angles,decorations.pathmorphing,through,shadings,backgrounds,positioning,fit,arrows.meta,shapes.misc,decorations.shapes}
\pgfdeclarelayer{background} %背景%底层
\pgfdeclarelayer{foreground} %上层
\pgfdeclarelayer{top} %顶部
\pgfdeclarelayer{bottom} %底部
\pgfsetlayers{bottom,background,main,foreground,top}
\RequirePackage[most]{tcolorbox}
\tcbuselibrary{breakable, skins,theorems,minted}
\makeatletter
\tcbset{my@basic@tcbthm/.style={detach title,}}
\newcommand{\@my@newtcbtheorem@n}[1]{\ERROR}
\newcommand{\@my@newtcbtheorem@nn}[2]{%
\@ifundefined{#1}{\@my@newtcbtheorem{#1}{#2}}{\@my@renewtcbtheorem{#1}{#2}}}
\newcommand{\@my@newtcbtheorem}[2]{%
\edef\my@curr@thmenvname{#1}% 它保存当前定理环境的名称
\mytcbtheoremset{#2}%
\NewTColorBox{#1}{ O{} O{} o }
{my@basic@tcbthm, my@#1@tcbthmstyle, title={##2}, IfNoValueF={##3}{label={##3}}, ##1}}
\newcommand{\@my@renewtcbtheorem}[2]{\edef\my@curr@thmenvname{#1}\mytcbtheoremset{#2}}
% 键值设置
\pgfkeys{/mytcbtheorem/.is family}
\newcommand{\mytcbtheoremset}{\pgfqkeys{/mytcbtheorem}}
\mytcbtheoremset{
name/.code=\@namedef{\my@curr@thmenvname @name}{#1}, %无效
counter/.code=\@namedef{my@\my@curr@thmenvname @counter}{#1}\newcounter{#1}[chapter],
% 计数器遇到subsection就会自动归零 % https://zhuanlan.zhihu.com/p/57454848#circle=on
the counter/.code=\@namedef{the\@nameuse{my@\my@curr@thmenvname @counter}}{#1},
autoref name/.code=\@namedef{\@nameuse{my@\my@curr@thmenvname @counter}autorefname}{#1},
style/.code=\tcbset{my@\my@curr@thmenvname @tcbthmstyle/.style={#1}},
thmcolor/.code=\@namedef{\my@curr@thmenvname @thmcolor}{#1}, %无效
lemcolor/.code=\@namedef{\my@curr@thmenvname @lemcolor}{#1}, %无效
}
% 存储键值 (LaTeX3)
\ExplSyntaxOn
\cs_new_protected:Npn \mynewtheorem
{ \keyval_parse:NNn \@my@newtheorem@n \@my@newtheorem@nn }
\cs_new_protected:Npn \mynewtcbtheorem
{ \keyval_parse:NNn \@my@newtcbtheorem@n \@my@newtcbtheorem@nn }
\ExplSyntaxOff
% /* ------------------ Second theorem style overlay settings ----------------- */
%%定义标题文字长度%%
\newlength{\thmtcbtextlen}
%%设置临界长度%%
\newlength{\thmcriticstarlen}
\setlength{\thmcriticstarlen}{.6\linewidth}
%
\def\my@thm@a#1#2{%
\begin{scope}
\path[
fill=#2,
drop shadow={shadow blur steps=10,shadow xshift=-1pt, shadow yshift=-1pt,shadow blur radius=1.5pt,shadow opacity=35}
]
node
[
append after command={
([xshift=-1.5*\rad]thmname.north west) to[out=0,in=180,looseness=1] ([xshift=2.5*\rad]thmname.south west) --([xshift=-\rad]thmname.south east) to[out=0,in=180,looseness=1] ([xshift=3*\rad]thmname.north east) --cycle},
text=white,font=\bfseries,align=center,inner ysep=1.5mm,minimum height=0.6cm,right
]
(thmname) at
([xshift=\rad,yshift=-.7*\rad]frame.north west)
{\hspace*{10pt}#1.\ \ifdefvoid{\tcbtitletext}{}{(\itshape\tcbtitletext)}};
%%============== 两边的阴影/折叠部分 ==============%%
\my@thm@a@layer{#1}{#2}
\end{scope}%
}
\def\my@thm@a@layer#1#2{%
\begin{pgfonlayer}{bottom}
% 左侧翅膀样式一
% \shade[left color=#2!20, right color=#2!80!black]
% ([xshift=-1.5*\rad]thmname.north west)
% to[out=180, in=0] ++(-2*\rad, -\rad)
% -| +(5*\rad,\rad)
% -- cycle;
% /* -------------------------------------------------------------------------- */
% 左侧翅膀样式二：镜像翻转为向上折叠效果
\shade[left color=#2!20, right color=#2!80!black]
([shift={(-.5*\rad,-\rad)}]thmname.north west)
to[out=180, in=0] ++(-2*\rad, \rad) % 将 -\rad 改为 \rad，使其向上延伸
-| +(5*\rad, -\rad) % 将 \rad 改为 -\rad，使其向下回到主体水平线
-- cycle;
% 右侧翅膀：完全镜像处理
% \shade[right color=#2!20, left color=#2!80!black]
% ([xshift=3*\rad]thmname.north east) % 注意这里起点需对应你核心代码中的 3*\rad
% to[out=0, in=180] ++(2*\rad, -\rad) % 镜像：out 180->0, in 0->180, x -2->2
% -| +(-5*\rad,\rad) % 镜像：x 5->-5
% -- cycle;
% ===== 右翅膀按条件切换 =====
%判断标题文字长度与临界长度的关系
\ifdim\thmtcbtextlen>\thmcriticstarlen
%-------- 右侧小翅膀：上下翻转版本 --------
\shade[right color=#2!20, left color=#2!80!black]
([xshift=2*\rad,yshift=-1*\rad]thmname.north east)
to[out=0, in=180] ++(2*\rad, \rad)
-| +(-5*\rad,-\rad)
-- cycle;
\else
% -------- 右侧小翅膀：原版本 --------
\shade[right color=#2!20, left color=#2!80!black]
([xshift=3*\rad]thmname.north east)
to[out=0, in=180] ++(2*\rad, -\rad)
-| +(-5*\rad,\rad)
-- cycle;
\fi
\end{pgfonlayer}
}
\def\my@thm@b#1#2{%
\begin{scope} % <--- 添加 scope 隔离环境
\path[fill=#2,
% drop shadow={opacity=0.3,shadow xshift=.3pt}
blur shadow={shadow blur steps=10,shadow xshift=-1pt, shadow yshift=-1pt,shadow blur radius=1.5pt,shadow opacity=35}
]
([xshift=-2*\rad,yshift=-5pt]frame.south east) coordinate (SE) to[out=0,in=180] +(4*\rad,5pt+\theight) --([shift={(-\tlen+4*\rad,5pt+\theight)}]SE) to[out=180,in=0] +(-4*\rad,-5pt-\theight) --cycle;
\begin{pgfonlayer}{bottom}
% 左侧翅膀：镜像翻转为向上折叠效果
\shade[left color=#2!20, right color=#2!80!black]
([shift={(-1.35*\tlen+\Rad,-5pt)}]frame.south east)
to[out=180, in=0] ++(-2*\rad, \rad) % 将 -\rad 改为 \rad，使其向上延伸
-| +(5*\rad, -\rad) % 将 \rad 改为 -\rad，使其向下回到主体水平线
-- cycle;
\end{pgfonlayer}
\end{scope}%
}
\newcommand{\my@lemma@overlay@unbroken}[2]{
%%============== First ==============%%
\def\rad{7pt}%
%%% 注意这里！
\begin{pgfinterruptpicture}
\settowidth{\thmtcbtextlen}{\hspace*{10pt}#1.\ \ifdefvoid{\tcbtitletext}{}{(\itshape\tcbtitletext)}}
% \global\thmtcbtextlen\thmtcbtextlen % \my@thm@a放到interrupt环境外面就需要global
\begin{tikzpicture}
% 这里可能需要调整细节！
\path[use as bounding box]([xshift=\rad]frame.north west) rectangle (frame.south east);
\my@thm@a{#1}{#2}%
\end{tikzpicture}
\end{pgfinterruptpicture}
% \my@thm@a{#1}{#2}% 把它放到单独的tikz环境里，如上
%
%%============== End ==============%%
\def\tlen{1.5cm}
\def\Rad{3.5pt}
\def\theight{0.5cm}
\my@thm@b{#1}{#2}
}
%% first 和 last 没在 MWE 里！
\newcommand\my@lemma@overlay@first[2]{
\def\rad{7pt}%
\begin{pgfinterruptpicture}
\settowidth{\thmtcbtextlen}{\hspace*{10pt}#1.\ \ifdefvoid{\tcbtitletext}{}{(\itshape\tcbtitletext)}}
% \global\thmtcbtextlen\thmtcbtextlen % \my@thm@a放到interrupt环境外面就需要global
\begin{tikzpicture}
\path[use as bounding box]([xshift=\rad]frame.north west) rectangle (frame.south east);
\my@thm@a{#1}{#2}%
\end{tikzpicture}
\end{pgfinterruptpicture}
}
\newcommand\my@lemma@overlay@last[1]{
\def\rad{7pt}%
\def\tlen{1.5cm}
\def\Rad{3.5pt}
\def\theight{0.5cm}
\my@thm@b{}{#1}
}
\mynewtcbtheorem{
theorem={
counter=tcbthm,
the counter=\thesection.\arabic{tcbthm},
autoref name=\bfseries Theorem,
style={
arc=0mm,breakable,enhanced,
% 针对跨页片段的特殊处理
extras first={
bottom=3mm, % 第一段的底部不需要留白
},
extras middle={
top=3mm, % 中间段的顶部不需要留白
bottom=0mm, % 中间段的底部不需要留白
},
extras last={
top=0mm, % 最后一段的顶部不需要留白
},
% 建议同时加入以下设置以确保彻底消除干扰
pad at break=2mm,
bottomsep at break=0mm,
topsep at break=2mm,
interior style={top color=黛绿!9 ,middle color=黛绿!6, bottom color=黛绿!3},arc=3pt,boxrule=0pt,top=6mm,bottom=5mm,
fuzzy shadow={-0.6mm}{0.6mm}{0mm}{0.3mm}{white!50!gray},% 上
fuzzy shadow={0.6mm}{-0.6mm}{0mm}{0.3mm}{fill=white!40!gray},%下
opacityframe=0, opacityback=0.98,
fontupper=\itshape,step={tcbthm},
before pre=\smallskip, after app=\smallskip,
overlay unbroken=\my@lemma@overlay@unbroken{Theorem\ \thetcbthm}{黛绿},
overlay first=\my@lemma@overlay@first{Theorem\ \thetcbthm}{黛绿},
overlay last=\my@lemma@overlay@last{黛绿},
}
},
}
\makeatother
\begin{document}
\chapter{Test}
\begin{theorem}[][Semidefinite vanishing theorem for vector bundle of rank $k$ (General Case)][thm:Semidefinite vanishing theorem for vector bundle of rank $k$ (General Case)]
Let $M$ be a compact complex manifold, and assume that there exists a hermitian metric on $E$, whose curvature tensor $\Theta$ satisfies the following condition at each point of $M$.
For any $\zeta\in C^r-0$, the quadratic form in $\eta,\Theta(\zeta,\eta)$, has at least $n-k_1$ positive eigenvalues and at least $k_2$ negative eigenvalues. Then
\[H^q(M,\Omega(S^\mu E\otimes D))=0\]
for any $q\not\in (k_1,\ldots,k_2)$ if $\mu\geq 0$.
\end{theorem}
\begin{theorem}[][lorem lipsum]
\lipsum[1-10]
\end{theorem}
\end{document}
问 tcolorbox盒子的定制问题