另一个基于plain-tikz的方案：
思路和上面基本一样，不过定点我用了tikz里其他的功能
\documentclass[tikz,border=5pt]{standalone}
\usetikzlibrary{calc,angles,quotes}
\begin{document}
\begin{tikzpicture}[line cap=round]
\coordinate (A) at (0,0);
\coordinate (B) at (4,0);
\coordinate (E) at (3,{sqrt(3)});
% 点D可以视为(3,0)绕点A逆时针旋转60度 用极坐标来写是「60：3」
\coordinate (D) at (60:3);
% 点C可以视为(3,0)绕点B顺时针旋转120度
% 看这个教程 https://tikz.dev/tikz-coordinates#sec-13.5.3
\coordinate (C) at ($(B)!1!-120:(3,0)$);
\draw[thick,cyan] (A) -- (B) -- (E) -- cycle;
\draw[thick,red] (A) -- (D) -- (C) -- (B);
\path (A) node[below left] {$A$}
(B) node[below] {$B$}
(C) node[right] {$C$}
(D) node[above] {$D$}
(E) node[above right] {$E$};
% 角度看这个教程 https://tikz.dev/library-angle#pgf.angles
\path
pic ["1",draw,cyan,thick,angle radius=.75cm,angle eccentricity=1.35] {angle = E--A--D}
pic ["2",draw,violet,thick,angle radius=.5cm,angle eccentricity=1.35] {angle = B--A--E}
pic ["3",draw,olive,thick,angle radius=.35cm,angle eccentricity=1.5] {angle = E--B--A}
pic ["4",draw,orange,thick,angle radius=.55cm,angle eccentricity=1.35] {angle = C--B--E}
;
\end{tikzpicture}
\end{document}
问 LaTeX 中绘图的思维流程