原代码
\documentclass{ctexart}
\usepackage{amsmath}
\usepackage[skins]{tcolorbox}
\newtheorem{Example}{例}
\newtheorem{MySolution}{解}
\tcolorboxenvironment{MySolution}{
colframe = blue!50!black, % 边框颜色
colback = blue!10, % 背景颜色
fonttitle = \bfseries, % 标题字体加粗
before upper = {\itshape}, % 内容字体为斜体
title = 解,
boxrule = 1pt % 边框宽度
}
\begin{document}
\begin{Example}
证明
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \ln 2.
\end{equation*}
\end{Example}
\begin{MySolution}
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \cdot \frac{1}{1 \mathrm{d}x} = \int_{0}^{1} \frac{1}{1} \cdot \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \mathrm{d}x.
\end{equation*}
因此
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \ln 2.
\end{equation*}
\end{MySolution}
\end{document}
如何去掉解字后面的这个序号呢?
\documentclass{ctexart}
\usepackage{amsthm}
\usepackage{amsmath}
\usepackage[skins]{tcolorbox}
\newtheorem{Example}{例}
\newtheorem*{MySolution}{解}
\tcolorboxenvironment{MySolution}{
colframe = blue!50!black, % 边框颜色
colback = blue!10, % 背景颜色
fonttitle = \bfseries, % 标题字体加粗
before upper = {\itshape}, % 内容字体为斜体
title = 解,
boxrule = 1pt % 边框宽度
}
\begin{document}
\begin{Example}
证明
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \ln 2.
\end{equation*}
\end{Example}
\begin{MySolution}
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \cdot \frac{1}{1 \mathrm{d}x} = \int_{0}^{1} \frac{1}{1} \cdot \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \mathrm{d}x.
\end{equation*}
因此
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \ln 2.
\end{equation*}
\end{MySolution}
\end{document}
当代码够短时,不要上传文件。实际上长的代码就不应该发上来提问。
查看tcolorbox
文档...
所以你的问题等价于,在\newtheorem
如何去掉1
?
请自行对比和思考下例:
\documentclass{ctexart}
\usepackage{amsmath}
\newtheorem{MySolution}{解}
\begin{document}
\begin{MySolution}
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \cdot \frac{1}{1 \mathrm{d}x} = \int_{0}^{1} \frac{1}{1} \cdot \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \mathrm{d}x.
\end{equation*}
\end{MySolution}
为什么会有\texttt{1}呢? 这一问题实际上与\texttt{tcolorbox}毫无关系.
\end{document}
\documentclass{ctexart}
\usepackage{amsmath}
\usepackage{amsthm}
\newtheorem*{MySolution}{解}
\begin{document}
\begin{MySolution}
\begin{equation*}
\int_{0}^{1} \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \cdot \frac{1}{1 \mathrm{d}x} = \int_{0}^{1} \frac{1}{1} \cdot \frac{1}{x} \mathrm{d}x = \int_{0}^{1} \frac{1}{x} \mathrm{d}x.
\end{equation*}
\end{MySolution}
\end{document}
对martin老师的解答做一点补充:
texdoc amsthm
: