在用TIKZ内intersections,calc宏包计算与X轴成150度、225度特殊角直线与圆的交点后,输出显示这些点的直角坐标、极坐标值时,发现有数值上的误差,用三角函数公式计算验证时就不是这些数值,这现象是如何引起的呢?

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{intersections, calc}
\begin{document}
\def\pttocm#1{\pgfmathparse{#1/28.45274}\pgfmathresult}
\makeatletter
\def\b{8}
\def\a{tan(225)}
\def\c{tan(150)}
\begin{tikzpicture}
\draw[->](-10,0) -- (10,0) node[right] {$x$};
\draw[->](0,-10) -- (0,10) node[left] {$y$};
\draw[name path global=m,black,line width=0.5pt,domain=0*pi:2*pi,samples=360] plot({\b*sin(\x r)},{\b*cos(\x r)});
\draw[name path global=n,black,line width=0.5pt,domain=0:-8,samples=10] plot(\x,{\a*\x});
\draw [name intersections={of=n and m, by=u}][teal,fill=orange](u) circle(5pt);
\draw[name path global=k,black,line width=0.5pt,domain=0:-8,samples=5] plot(\x,{\c*\x});
\draw [name intersections={of=k and m, by=s}][teal,fill=orange](s) circle(5pt);
\pgfpointanchor{u}{center}
\pgfgetlastxy{\ux}{\uy}
\pgfpointanchor{s}{center}
\pgfgetlastxy{\sx}{\sy}
\fill[purple,font=\Large] let \p1=(u) in (\p1) circle (2pt) node at(-3,-5) {$[x=\pttocm{\the\pgf@x}]$};
\fill[purple,font=\Large] let \p1=(u) in (\p1) circle (2pt) node at(-3,-5.75) {$[y=\pttocm{\the\pgf@y}]$};
\fill[purple,font=\Large] let \p1=(s) in (\p1) circle (2pt) node at(-3,5.75) {$[x=\pttocm{\the\pgf@x}]$};
\fill[purple,font=\Large] let \p1=(s) in (\p1) circle (2pt) node at(-3,5) {$[y=\pttocm{\the\pgf@y}]$};
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\coordinate (A) at (0,0);
\coordinate (B) at (\ux,\uy);
\coordinate (C) at (\sx,\sy);
\pgfmathanglebetweenpoints{\pgfpointanchor{A}{center}}{\pgfpointanchor{B}{center}}
\edef\angle{\pgfmathresult}
\node at (-5.5,-6.75) [blue,font=\Large] {$[\rho=\b]$};
\node at (-4.5,-7.5) [blue,font=\Large] {$[\theta=\angle^\circ]$};
\pgfmathanglebetweenpoints{\pgfpointanchor{A}{center}}{\pgfpointanchor{C}{center}}
\edef\angle{\pgfmathresult}
\node at (-1.5,4.25) [blue,font=\Large] {$[\rho=\b]$};
\node at (-0.5,3.5) [blue,font=\Large] {$[\theta=\angle^\circ]$};
\end{tikzpicture}
\end{document}